Cheatsheet for dplyr join functions
Jenny Bryan
11 September, 2014
Why the cheatsheet
Examples for those of us who don't speak SQL so good. There are lots of Venn diagrams re: SQL joins on the interwebs, but I wanted R examples.
Full documentation for the dplyr
package, which is developed by Hadley Wickham and Romain Francois on GitHub.
Working with two small data.frames, superheroes
and publishers
.
suppressPackageStartupMessages(library(dplyr))
superheroes <-
c(" name, alignment, gender, publisher",
" Magneto, bad, male, Marvel",
" Storm, good, female, Marvel",
"Mystique, bad, female, Marvel",
" Batman, good, male, DC",
" Joker, bad, male, DC",
"Catwoman, bad, female, DC",
" Hellboy, good, male, Dark Horse Comics")
superheroes <- read.csv(text = superheroes, strip.white = TRUE)
publishers <-
c("publisher, yr_founded",
" DC, 1934",
" Marvel, 1939",
" Image, 1992")
publishers <- read.csv(text = publishers, strip.white = TRUE)
Sorry, cheat sheet does not illustrate "multiple match" situations terribly well.
Sub-plot: watch the row and variable order of the join results for a healthy reminder of why it's dangerous to rely on any of that in an analysis.
inner_join(superheroes, publishers)
inner_join(x, y): return all rows from x where there are matching values in y, and all columns from x and y. If there are multiple matches between x and y, all combination of the matches are returned
(ijsp <- inner_join(superheroes, publishers))
## Joining by: "publisher"
## name alignment gender publisher yr_founded
## 1 Magneto bad male Marvel 1939
## 2 Storm good female Marvel 1939
## 3 Mystique bad female Marvel 1939
## 4 Batman good male DC 1934
## 5 Joker bad male DC 1934
## 6 Catwoman bad female DC 1934
We lose Hellboy in the join because, although he appears in x = superheroes
, his publisher Dark Horse Comics does not appear in y = publishers
. The join result has all variables from x = superheroes
plus yr_founded
, from y
.
superheroes |name |alignment |gender |publisher | |:--------|:---------|:------|:-----------------| |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Hellboy |good |male |Dark Horse Comics | | publishers |publisher | yr_founded| |:---------|----------:| |DC | 1934| |Marvel | 1939| |Image | 1992| | inner_join(x = superheroes, y = publishers) |name |alignment |gender |publisher | yr_founded| |:--------|:---------|:------|:---------|----------:| |Magneto |bad |male |Marvel | 1939| |Storm |good |female |Marvel | 1939| |Mystique |bad |female |Marvel | 1939| |Batman |good |male |DC | 1934| |Joker |bad |male |DC | 1934| |Catwoman |bad |female |DC | 1934| |
semi_join(superheroes, publishers)
semi_join(x, y): return all rows from x where there are matching values in y, keeping just columns from x. A semi join differs from an inner join because an inner join will return one row of x for each matching row of y, where a semi join will never duplicate rows of x.
(sjsp <- semi_join(superheroes, publishers))
## Joining by: "publisher"
## name alignment gender publisher
## 1 Batman good male DC
## 2 Joker bad male DC
## 3 Catwoman bad female DC
## 4 Magneto bad male Marvel
## 5 Storm good female Marvel
## 6 Mystique bad female Marvel
We get a similar result as with inner_join()
but the join result contains only the variables originally found in x = superheroes
.
superheroes |name |alignment |gender |publisher | |:--------|:---------|:------|:-----------------| |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Hellboy |good |male |Dark Horse Comics | | publishers |publisher | yr_founded| |:---------|----------:| |DC | 1934| |Marvel | 1939| |Image | 1992| | semi-join(x = superheroes, y = publishers) |name |alignment |gender |publisher | |:--------|:---------|:------|:---------| |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |
left_join(superheroes, publishers)
left_join(x, y): return all rows from x, and all columns from x and y. If there are multiple matches between x and y, all combination of the matches are returned
(ljsp <- left_join(superheroes, publishers))
## Joining by: "publisher"
## name alignment gender publisher yr_founded
## 1 Magneto bad male Marvel 1939
## 2 Storm good female Marvel 1939
## 3 Mystique bad female Marvel 1939
## 4 Batman good male DC 1934
## 5 Joker bad male DC 1934
## 6 Catwoman bad female DC 1934
## 7 Hellboy good male Dark Horse Comics NA
We basically get x = superheroes
back, but with the addition of variable yr_founded
, which is unique to y = publishers
. Hellboy, whose publisher does not appear in y = publishers
, has an NA
for yr_founded
.
superheroes |name |alignment |gender |publisher | |:--------|:---------|:------|:-----------------| |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Hellboy |good |male |Dark Horse Comics | | publishers |publisher | yr_founded| |:---------|----------:| |DC | 1934| |Marvel | 1939| |Image | 1992| | left_join(x = superheroes, y = publishers) |name |alignment |gender |publisher | yr_founded| |:--------|:---------|:------|:-----------------|----------:| |Magneto |bad |male |Marvel | 1939| |Storm |good |female |Marvel | 1939| |Mystique |bad |female |Marvel | 1939| |Batman |good |male |DC | 1934| |Joker |bad |male |DC | 1934| |Catwoman |bad |female |DC | 1934| |Hellboy |good |male |Dark Horse Comics | NA| |
anti_join(superheroes, publishers)
anti_join(x, y): return all rows from x where there are not matching values in y, keeping just columns from x
(ajsp <- anti_join(superheroes, publishers))
## Joining by: "publisher"
## name alignment gender publisher
## 1 Hellboy good male Dark Horse Comics
We keep only Hellboy now (and do not get yr_founded
).
superheroes |name |alignment |gender |publisher | |:--------|:---------|:------|:-----------------| |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Hellboy |good |male |Dark Horse Comics | | publishers |publisher | yr_founded| |:---------|----------:| |DC | 1934| |Marvel | 1939| |Image | 1992| | anti_join(x = superheroes, y = publishers) |name |alignment |gender |publisher | |:-------|:---------|:------|:-----------------| |Hellboy |good |male |Dark Horse Comics | |
inner_join(publishers, superheroes)
inner_join(x, y): return all rows from x where there are matching values in y, and all columns from x and y. If there are multiple matches between x and y, all combination of the matches are returned
(ijps <- inner_join(publishers, superheroes))
## Joining by: "publisher"
## publisher yr_founded name alignment gender
## 1 Marvel 1939 Magneto bad male
## 2 Marvel 1939 Storm good female
## 3 Marvel 1939 Mystique bad female
## 4 DC 1934 Batman good male
## 5 DC 1934 Joker bad male
## 6 DC 1934 Catwoman bad female
In a way, this does illustrate multiple matches, if you think about it from the x = publishers
direction. Every publisher that has a match in y = superheroes
appears multiple times in the result, once for each match. In fact, we're getting the same result as with inner_join(superheroes, publishers)
, up to variable order (which you should also never rely on in an analysis).
superheroes |publisher | yr_founded| |:---------|----------:| |DC | 1934| |Marvel | 1939| |Image | 1992| | publishers |name |alignment |gender |publisher | |:--------|:---------|:------|:-----------------| |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Hellboy |good |male |Dark Horse Comics | | inner_join(x = publishers, y = superheroes) |publisher | yr_founded|name |alignment |gender | |:---------|----------:|:--------|:---------|:------| |Marvel | 1939|Magneto |bad |male | |Marvel | 1939|Storm |good |female | |Marvel | 1939|Mystique |bad |female | |DC | 1934|Batman |good |male | |DC | 1934|Joker |bad |male | |DC | 1934|Catwoman |bad |female | |
semi_join(publishers, superheroes)
semi_join(x, y): return all rows from x where there are matching values in y, keeping just columns from x. A semi join differs from an inner join because an inner join will return one row of x for each matching row of y, where a semi join will never duplicate rows of x.
(sjps <- semi_join(x = publishers, y = superheroes))
## Joining by: "publisher"
## publisher yr_founded
## 1 Marvel 1939
## 2 DC 1934
Now the effects of switching the x
and y
roles is more clear. The result resembles x = publishers
, but the publisher Image is lost, because there are no observations where publisher == "Image"
in y = superheroes
.
superheroes |publisher | yr_founded| |:---------|----------:| |DC | 1934| |Marvel | 1939| |Image | 1992| | publishers |name |alignment |gender |publisher | |:--------|:---------|:------|:-----------------| |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Hellboy |good |male |Dark Horse Comics | | semi-join(x = publishers, y = superheroes) |publisher | yr_founded| |:---------|----------:| |Marvel | 1939| |DC | 1934| |
left_join(publishers, superheroes)
left_join(x, y): return all rows from x, and all columns from x and y. If there are multiple matches between x and y, all combination of the matches are returned
(ljps <- left_join(publishers, superheroes))
## Joining by: "publisher"
## publisher yr_founded name alignment gender
## 1 DC 1934 Batman good male
## 2 DC 1934 Joker bad male
## 3 DC 1934 Catwoman bad female
## 4 Marvel 1939 Magneto bad male
## 5 Marvel 1939 Storm good female
## 6 Marvel 1939 Mystique bad female
## 7 Image 1992 <NA> <NA> <NA>
We get a similar result as with inner_join()
but the publisher Image survives in the join, even though no superheroes from Image appear in y = superheroes
. As a result, Image has NA
s for name
, alignment
, and gender
.
publishers |publisher | yr_founded| |:---------|----------:| |DC | 1934| |Marvel | 1939| |Image | 1992| | superheroes |name |alignment |gender |publisher | |:--------|:---------|:------|:-----------------| |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Hellboy |good |male |Dark Horse Comics | | left_join(x = publishers, y = superheroes) |publisher | yr_founded|name |alignment |gender | |:---------|----------:|:--------|:---------|:------| |DC | 1934|Batman |good |male | |DC | 1934|Joker |bad |male | |DC | 1934|Catwoman |bad |female | |Marvel | 1939|Magneto |bad |male | |Marvel | 1939|Storm |good |female | |Marvel | 1939|Mystique |bad |female | |Image | 1992|NA |NA |NA | |
anti_join(publishers, superheroes)
anti_join(x, y): return all rows from x where there are not matching values in y, keeping just columns from x
(ajps <- anti_join(publishers, superheroes))
## Joining by: "publisher"
## publisher yr_founded
## 1 Image 1992
We keep only publisher Image now (and the variables found in x = publishers
).
publishers |publisher | yr_founded| |:---------|----------:| |DC | 1934| |Marvel | 1939| |Image | 1992| | superheroes |name |alignment |gender |publisher | |:--------|:---------|:------|:-----------------| |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Hellboy |good |male |Dark Horse Comics | | anti_join(x = publishers, y = superheroes) |publisher | yr_founded| |:---------|----------:| |Image | 1992| |
NOT dplyr: merge(superheroes, publishers, all = TRUE)
What if you want to merge two data.frames and keep rows that appear in either? In SQL jargon, this is an outer join and is not yet implemented in dplyr
, though it will come. In the meantime, you could use merge()
from base R.
merge(x, y): Merge two data frames by common columns or row names, or do other versions of database join operations
(OJsp <- merge(superheroes, publishers, all = TRUE))
## publisher name alignment gender yr_founded
## 1 Dark Horse Comics Hellboy good male NA
## 2 DC Batman good male 1934
## 3 DC Joker bad male 1934
## 4 DC Catwoman bad female 1934
## 5 Marvel Magneto bad male 1939
## 6 Marvel Storm good female 1939
## 7 Marvel Mystique bad female 1939
## 8 Image <NA> <NA> <NA> 1992
We keep Hellboy (whose publisher Dark Horse Comics is not in publishers
) and Image (a publisher with no superheroes in superheroes
) and get variables from both data.frames. Therefore observations for which there is no match in the two data.frames carry NA
s in the variables from the other data source.
superheroes |name |alignment |gender |publisher | |:--------|:---------|:------|:-----------------| |Magneto |bad |male |Marvel | |Storm |good |female |Marvel | |Mystique |bad |female |Marvel | |Batman |good |male |DC | |Joker |bad |male |DC | |Catwoman |bad |female |DC | |Hellboy |good |male |Dark Horse Comics | | publishers |publisher | yr_founded| |:---------|----------:| |DC | 1934| |Marvel | 1939| |Image | 1992| | merge(superheroes, publishers, all = TRUE) |publisher |name |alignment |gender | yr_founded| |:-----------------|:--------|:---------|:------|----------:| |Dark Horse Comics |Hellboy |good |male | NA| |DC |Batman |good |male | 1934| |DC |Joker |bad |male | 1934| |DC |Catwoman |bad |female | 1934| |Marvel |Magneto |bad |male | 1939| |Marvel |Storm |good |female | 1939| |Marvel |Mystique |bad |female | 1939| |Image |NA |NA |NA | 1992| |
sessionInfo()
sessionInfo()
## R version 3.1.0 (2014-04-10)
## Platform: x86_64-apple-darwin10.8.0 (64-bit)
##
## locale:
## [1] en_CA.UTF-8/en_CA.UTF-8/en_CA.UTF-8/C/en_CA.UTF-8/en_CA.UTF-8
##
## attached base packages:
## [1] stats graphics grDevices utils datasets methods base
##
## other attached packages:
## [1] dplyr_0.2.0.99
##
## loaded via a namespace (and not attached):
## [1] assertthat_0.1 digest_0.6.4 evaluate_0.5.5 formatR_0.10
## [5] htmltools_0.2.4 knitr_1.6 magrittr_1.0.1 parallel_3.1.0
## [9] Rcpp_0.11.1 rmarkdown_0.2.64 stringr_0.6.2 tools_3.1.0
## [13] yaml_2.1.13